In Fig. 12.33, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region.
Area of quadrant = 
2
= 
2
=154 sq cm
Area of triangle= 1/2 *b *h
= 1/2 *14 *14
= 98 sq cm
Area of segment made by hypotenuse of triangle = 154 – 98
= 56 sq cm
Since other two sides of triangle are 14cm
Therefore,
Diameter of external semicircle = 
So, area of the semicircle = 1/2 
2
= 
2
= 154 sq cm
Area of the shaded region = 154 – 56
= 98 sq cm
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