Solve the following equations:
![]()
Given Differential equation is:
⇒ ![]()
⇒
……(1)
Homogeneous equation: A equation is said to be homogeneous if f(zx,zy) = znf(x,y) (where n is the order of the homogeneous equation).
Let us assume:

⇒ 
⇒ 
⇒ 
⇒ f(zx,zy) = z0f(x,y)
So, given differential equation is a homogeneous differential equation.
We need a substitution to solve this type of linear equation and the substitution is x = vy.
Let us substitute this in (1)
⇒ 
We know that:
![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
Bringing like variables on the same side we get,
⇒ ![]()
We know that ∫exdx = ex + C and
![]()
Integrating on both sides, we get,
⇒ ![]()
⇒ ev = logy + C
Since x = vy, we get ![]()
⇒ ![]()
∴ The solution for the given Differential equation is
.