Solve the following differential equations :
Formula:-
(i) if a differential equation is ,
then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx
(ii) ∫dx = x + c
Here,
This is a linear differential equation, comparing it with
P = 2, Q = 6ex
I.F = e∫Pdx
= e∫2Pdx
= e2x
Solution of the equation is given by
y(I.F) = ∫Q.(I.F)dx + c
⇒ ye2x = ∫6ex e2x dx + c
⇒ ye2x = ∫6e3x dx + c
⇒ ye2x = 2e3x + c
⇒ y = 2e3x + ce–2x