Solve the following differential equations :
(i) If a differential equation is ,
then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx
(ii) ∫dx = x + c
given:
This is a linear differential equation, comparing it with
P = 1, Q = sinx
I.F = e∫Pdx
= e∫dx
= ex
Solution of the equation is given by
y(I.F) = ∫Q.(I.F)dx + c
⇒ y ex = ∫sinx. ex dx + c