Solve the following differential equations :

(i) If a differential equation is ,


then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx





Given:-



This is a linear differential equation, comparing it with




I.F = e∫Pdx




Solution of the equation is given by


y(I.F) = ∫Q.(I.F)dx + c





so,


yt = ∫t.dt + c





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