Solve the following differential equations :
xdy = (2y + 2x4 + x2)dx
(i) If a differential equation is ,
then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx
Given:-
This is a linear differential equation, comparing it with
,
Q = 2x3 + x
I.F = e∫Pdx
= e–2logx
=
Solution of the equation is given by
y(I.F) = ∫Q.(I.F)dx + c