Solve the following differential equations :

xdy = (2y + 2x4 + x2)dx

(i) If a differential equation is ,


then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx






Given:-



This is a linear differential equation, comparing it with



,


Q = 2x3 + x


I.F = e∫Pdx



= e–2logx



=


Solution of the equation is given by


y(I.F) = ∫Q.(I.F)dx + c





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