Find the values of y for which the distance between the points P(2, – 3) and Q (10, y) is10 units

It is given that the distance between (2, - 3) and (10, y) is 10

Therefore,


[(2 - 10)2 + (-3- y)2]1/2 = 10


[(-8)2 + (3+ y)2]1/2 = 10


64 + (y + 3)2 = 100


(y + 3)2 = 36


y + 3 =


y + 3 = 6 or y + 3 = -6


Therefore, y = 3 or -9


31