Find the coordinates of the tip of the position vector which is equivalent to 
where the coordinates of A and B are (-1, 3) and (-2, 1) respectively.
Given A = (–1, 3) and B = (–2, 1)
We know position vector of a point (x, y) is given by
, where 
and 
are unit vectors in X and Y directions.
Let position vectors of points A and B be 
and 
respectively.
We also have
.
Recall the vector 
is given by
Now, it is given that there exists a point say (x, y) whose position vector is same as
.
We know position vector of a point (x, y) is given by
.
By comparing both the sides, we get x = –1 and y = –2
Thus, (–1, –2) is the tip of position vector that is same as 
.
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