If Q(0, 1) is equidistant from P(5, –3) and R(x, 6), find the values of x. Also find the distances QR and PR
PQ = QR
[(5 - 0)2 + (-3- 1)2]1/2= [(0 - x)2 + (1- 6)2]1/2
= 
41 = x2 + 25
x2 = 16
x = 
Hence, point R is (4, 6) or ( - 4, 6).
When point R is (4, 6)
PR = [(5 - 4)2 + (-3 - 6)2]1/2
= 
= 
QR = [(0 - 4)2 + (1 - 6)2]1/2
= 
= 
When point R is (- 4, 6),
PR = [(5 + 4)2 + (-3 - 6)2]1/2
= 
= 9
QR = [(0+ 4)2 + (1 - 6)2]1/2
= 
= 
12