Find a relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (– 3, 4)
Point (x, y) is equidistant from (3, 6) and (- 3, 4)
Therefore,
[(x- 3)2 + (y - 6)2]1/2 = [(x + 3)2 + (y- 4)2]1/2
(x – 3)2 + (y – 6)2 = (x + 3)2 + (y – 4)2
x2 + 9 – 6x + y2 + 36 – 12y = x2 + 9 + 6x + y2 + 16 – 8y
36 – 16 = 6x + 6x + 12y – 8y
20 = 12x + 4y
3x + y = 5
3x + y – 5 = 0