Show that the direction cosines of a vector equally inclined to the axes OX, OY and OZ are
Let a vector be equally inclined to axes OX, OY, and OZ at angle
Then, the direction cosines of the vector are l = cosα, m = cosα and n = cos α
And, we know that –
l2 + m2 + n2 = 1
cos2α + cos2α + cos2α = 1
3 cos2α = 1
Hence, the direction cosines of the vector which are equally inclined to the axes are