Find the area of the region common to the parabolas 4y2 = 9x and 3 x2 =16y.

The given equations are,


4y2 = 9x



And 3x2 = 16y.



Equating equation (i) and (ii)



Or


Or x = 4


When we put x = 4 in equation (i) then y = 3,


When we put x = 0 in equation (i) then y = 0,


On solving these two equations, we get the point of intersections.


The points are O (0, 0) and A(4,3). These are shown in the graph below



Now the bounded area is the required area to be calculated, Hence,


Bounded Area, A = [Area between the curve (i) and x axis from 0 to 4] - [Area between the curve (ii) and x axis from 0 to 4]




On integrating the above definite integration,


The required area =






Area of the region common to the parabolas 4y2 = 9x and 3 x2 = 16y is 4 sq. units


2