To find the area enclosed by,

y = 2x² ...(i)

And y = x² + 4 ...(ii)

On solving the equation (i) and (ii),

2x² = x² + 4

Or x² = 4

Or x =

y = 8

Equation (1) represents a parabola with vertex (0,0) and axis as y - axis.

Equation (2) represents a parabola with vertex (0,4) and axis as the y - axis.

Points of intersection of parabolas are A(2,8) and B( – 2,8).

These are shown in the graph below: -

Required area = Region AOBCA

= 2(Region AOCA)

Hence, proved that the area common to the two parabolas y = 2x² and y = x² + 4 is 32/3 sq. Units.