Find the area of the region in the first quadrant enclosed by the x - axis, the line y = √3x and the circle x2 + y2 = 16.

To find the area enclosed by

y = √3x ...(i)


x2 + y2 = 16 ...(ii)


On solving the equation (i) and (ii),


Or x2 + = 16


Or 4x2 = 16


Or x2 = 4


Or x =


Y = ±


Equation (i) represents a parabola with vertex (0,0) and axis as x - axis.


Equation (ii) represent axis a circle with centre (4,0) and meets axes at (0,0) and (4,0).


They intersect at A (2,) and C ( – 2, – ).


These are shown in the graph below: -



Area of the region OAB = Area OAC + Area ACB









The area of the region in the first quadrant enclosed by x - axis, the line y = √3x and the circle x2 + y2 = 16 is


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