The surface area of a balloon being inflated, changes at a rate proportional to time t. If initially its radius is 1 unit and after 3 seconds it is 2 units, find the radius after time t.
Let the surface area of the balloon be S.
∴ S = 4πr2
According to the question,
⇒
⇒
⇒ 8πr
⇒ 8πrdr = ktdt
Integrating both sides, we have
⇒ 8π∫rdr = k∫tdt
⇒
⇒ ……(1)
Given, we have r = 1 unit when the t = 0 sec
Putting the value in equation (1)
∴
⇒ 4π (1)2 = k × 0 + c
⇒ c = 4π ……(2)
Putting the value of c in equation (1) we have,
……(3)
Given, we have r = 2 units when t = 3 sec
∴
⇒
⇒
⇒ ……(4)
Now, putting the value of k in equation (2),
We have,
⇒
⇒
⇒
⇒
∴