Find the acute angle between the lines whose direction ratios are proportional to 2:3:6 and 1:2:2.

Given that the direction ratios of the lines are proportional to 2:3:6 and 1:2:2.


Let us denote the lines in the form of vectors as A and B.


Let’s write the vectors:


A = 2i + 3j + 6k


B = 1i + 2j + 2k


We know that the angle between the vectors a1i + b1j + c1k and a2i + b2j + c2k is given by:



Let’s assume the angle between the vectors A and B be ,


Using the given formula we find the value of .







The acute angle between the two vectors is given by .


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