Given
being a right handed orthogonal system of unit vectors in space, show that
is also another system.
To show that,
,
is a right handed orthogonal system of unit vectors, we need to prove the following –
(a)
(b)
(c)
(d)
Let us consider each of these one at a time.
(a) Recall the magnitude of the vector is
First, we will find.
Now, we will find.
Finally, we will find.
Hence, we have
(b) Now, we will evaluate the vector
Recall the cross product of two vectors and
is
Taking the scalar common, here, we have (a1, a2, a3) = (2, 3, 6) and (b1, b2, b3) = (3, –6, 2)
Hence, we have.
(c) Now, we will evaluate the vector
Taking the scalar common, here, we have (a1, a2, a3) = (3, –6, 2) and (b1, b2, b3) = (6, 2, –3)
Hence, we have.
(d) Now, we will evaluate the vector
Taking the scalar common, here, we have (a1, a2, a3) = (6, 2, –3) and (b1, b2, b3) = (2, 3, 6)
Hence, we have.
Thus,,
,
is also another right handed orthogonal system of unit vectors.