ABCD is a parallelogram. The position vectors of the points A, B and C are respectively,
and
Find the vector equation of the line BD. Also, reduce it to Cartesian form.

Given: the vectors of point A =
, B =
and
C = ![]()
this means that the vector equation of line AB is given by
![]()
where
and ![]()
![]()
so the vector equation of AB is
![]()
now the vector equation of BC is given as
![]()
where
and ![]()
![]()
therefore the vector equation of BC is given as
![]()
The concept of the question:
the vector equation of the diagonal BD is given by
![]()
and the vector equation of diagonal AC is given by
![]()

……(1)
can be written as
…..(2)
Comparing 1&2
x = –2–
, y = –8 + 13
, z = 14–17![]()
![]()
Therefore, a cartesian equation of the required line is
![]()