Find the direction cosines of the line Also, reduce it to vector form.

the equation of the line is


But to make it cartesian equation the coefficient of x, y, z must be one so the above equation becomes as



Now the direction ratios of this line is ‹–2, 6, –3›


Concept of the question


Direction cosines of line



Are given as


Here




Hence direction cosines of the above line are



cartesian equation of the line is



Let this be equal to



Hence ….(1)


….(2)


Hence comparing 1&2



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