Find the direction cosines of the line Also, reduce it to vector form.
the equation of the line is
But to make it cartesian equation the coefficient of x, y, z must be one so the above equation becomes as
Now the direction ratios of this line is ‹–2, 6, –3›
Concept of the question
Direction cosines of line
Are given as
Here
Hence direction cosines of the above line are
cartesian equation of the line is
Let this be equal to
Hence ….(1)
….(2)
Hence comparing 1&2