Prove that the lines through A(0, – 1, – 1) and B(4, 5, 1) intersects the line through C(3, 9, 4) and D( – 4, 4, 4). Also, find their point of intersection.
Given: - Line joining A(0, – 1, – 1) and B(4, 5, 1).
Line joining C(3, 9, 4) and D( – 4, 4, 4).
To Prove: - Both lines intersects
Proof: - Equation of a line joined by two points A(x1,y1,z1) and B(x2,y2,z2) is given by
Now equation of line joining A(0, – 1, – 1) and B(4, 5, 1)
=
⇒ x = 4λ, y = 6λ – 1 and z = 2λ – 1
So, the coordinates of a general point on this line are
(4λ, 6λ – 1, 2λ – 1)
And equation of line joining C(3, 9, 4) and D( – 4, 4, 4)
=
⇒ x = – 7μ + 3, y = – 5μ + 9 and z = 4
So, the coordinates of a general point on this line are
( – 7μ + 3, – 5μ + 9, 4)
If the lines intersect, then they must have a common point.
Therefore for some value of λ and μ, we have
⇒ 4λ = – 7μ + 3 , 6λ – 1 = – 5μ + 9, and 2λ – 1 = 4
⇒ ……(i)
⇒ 6λ + 5μ = 10 ……(ii)
and 2λ = 5 ……(iii)
from eq iii, we get
⇒
Now putting the value of λ in eq i, we get
⇒
⇒ – 1
As we can see by putting the value of λ and μ in eq ii, that it satisfy the equation.
Check
⇒ 6λ + 5μ = 10
⇒
⇒
⇒ 10 = 10
⇒ LHS = RHS ;Hence intersection point exist or line do intersects
We can find intersecting point by putting values of μ or λ in any one general point equation
Thus,
Intersection point
– 7μ + 3, – 5μ + 9, 4
– 7( – 1) + 3, – 5( – 1) + 9, 4
10, 14, 4