Given: - Point P(2, 4, – 1) and equation of line

Let, Q be a point through which line passes

Thus from given equation of line coordinates of Q is

Q( – 5, – 3,6)

As we know line equation with direction ratio of given line is parallel to given line.

Hence Line is parallel to

Now,

⇒

⇒

Now let's find cross product of this two vectors

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The magnitude of this cross product

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And Magnitude of

⇒

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Thus distance of point from line is

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⇒ units