Find the equation of the plane passing through the following points:

(– 5, 0, – 6), (– 3, 10, – 9) and (– 2, 6, – 6)

If the given points are then the equation of the plane passing through these three points is given by the following equation.



Now substitute the values given




Now apply the determinant



(x + 5)(0 + 18) – y(0 + 9) + (z + 6)(12 – 30) = 0


(x + 5)(18) – y(9) + (z + 6)(– 18) = 0


18x + 90 – 9y – 18z – 108 = 0


Now divide both sides 9 then we get the plane equation as


2x – y – 2z – 2 = 0


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