Reduce the equations of the following planes in the intercept form and find its intercepts on the coordinate axes:

Question

Reduce the equations of the following planes in the intercept form and find its intercepts on the coordinate axes: 4x + 3y – 6z – 12 = 0

Philoid · Accepted Answer

given equation is 4x + 3y – 6z – 12 = 0

4x + 3y – 6z = 12

Now let us divide both sides by 12

We get,

We know that, the equation of the plane whose intercepts on the coordinate axes a, b, c is given by the equation

So by comparing a = 3, b = 4, c = – 2

So the intercepts are 3, 4, – 2