Reduce the equations of the following planes in the intercept form and find its intercepts on the coordinate axes:

Question

Reduce the equations of the following planes in the intercept form and find its intercepts on the coordinate axes: 2x + 3y – z = 6

Philoid · Accepted Answer

given equation is 2x + 3y – z = 6

Now let us divide both sides by 6

We get,

We know that, the equation of the plane whose intercepts on the coordinate axes a, b, c is given by the equation

So by comparing a = 3, b = 2, c = – 6

So the intercepts are 3, 2, – 6.