The direction ratios of the perpendicular from the origin to a plane are 12, – 3, 4 and the length of the perpendicular is 5. Find the equation of the plane.
It is given that the direction ratios of the normal vector 
is 12, – 3, and 4.
So, 
|
| = 
Now, 
Length of the perpendicular from the origin to the plane, d = 5
The equation of the plane in normal form is
6