Find the equation of the plane passing through the point (1,2,1) and perpendicular to the line joining the points (1,4,2) and (2,3,5). Find also the perpendicular distance of the origin from this plane.
We know that the vector equation of the plane passing through a point
and normal to
is
……(i)
Here,
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And, ![]()
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Putting the value of
and
in (i)
.
.
.
.
……(ii)
![]()
Dividing (ii) by ![]()
![]()
![]()
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So the perpendicular distance of plane from origin =
units
Equation of plane: ![]()
Equation of plane : x – y + 3z – 2 = 0.