Find the angle between the planes :

x + y – 2z = 3 and 2x – 2y + z = 5

Given planes are x + y – 2z = 3 and 2x – 2y + z = 5


We know that angle between two planes,


a1x + b1y + c1z + d1 = 0


a2x + b2y + c2z + d2 = 0 is given as



Here we have,


a1 = 1, b1 = 1, c1 = – 2


a2 = 2, b2 = – 2, c2 = 1







Hence, the angle between planes x + y – 2z = 3 and 2x – 2y + z = 5 is


2