Find the angle between the planes :

2x – 3y + 4z = 1 and –x + y = 4

Given planes are 2x – 3y + 4z = 1 and – x + y = 4


We know that angle between two planes,


a1x + b1y + c1z + d1 = 0


a2x + b2y + c2z + d2 = 0 is given as



Here we have,


a1 = 2, b1 = – 3, c1 = 4


a2 = – 1, b2 = 1, c2 = 0







Hence, the angle between planes 2x – 3y + 4z = 1 and – x + y = 4 is


2