Find the Cartesian form of the equation of the following planes :

We have,





Now, we know that represents a plane passing through a point having position vector and parallel to the vectors .


Clearly, .


Now, the plane is perpendicular to ,


Hence




We know that vector equation of a plane in scalar product form is given as


Put and in equation (a) we get,






Put


We have,


2y – z = 1


Hence, the required equation of plane is 2y – z = 1


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