Given Eq. of plane is 2x – 3y + z = 0 …… (1)

We know that equation of a plane parallel to given plane (1) is

2x – 3y + z + k = 0 …… (2)

As given that , plane (2) is passing through the point (1, – 1,2) so it satisfy the plane (2),

2(1) – 3( – 1) + (2) + k = 0

2 + 3 + 2 + k = 0

7 + k = 0

k = – 7

put the value of k in equation (2),

2x – 3y + z – 7 = 0

So, equation of the required plane is , 2x – 3y + z = 7