Find the equation of the plane passing through the intersection of the planes
and the point (2, 1, 3).
We know that, the equation of a plane through the line of intersection of the plane
and ![]()
is given by ![]()
So, equation of plane passing through the line of intersection of plane
and
is given by
![]()
…… (1)
Given that plane (1) is passing through
so
![]()
(2)(2 + 2k) + (1)(1 + 5k) + (3)(3 + 3k) – 7 – 9k = 0
4 + 4k + 1 + 5k + 9 + 9k – 7 – 9k = 0
9k = – 7
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Put the value of k in equation (1),
![]()
![]()
![]()
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Multiplying by (
), we get
![]()
Equation of required plane is , ![]()