A die is thrown twice. What is the probability that (i) 5 will not come up either time? (ii) 5 will come up at least once? [Hint: Throwing a die twice and throwing two dice simultaneously are treated as the same experiment]

Question

Philoid · Accepted Answer

Total number of outcomes = 6 × 6

= 36

(i)Total number of outcomes when 5 comes up on either time are (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (1, 5), (2, 5),

(3, 5), (4, 5), (6, 5)

Therefore, the total number of favourable cases = 11

P (5 will come up either time) =

P (5 will not come up either time) = 1 -

=

(ii)Total number of cases, where 5 comes at least once = 11

P (5 will come at least once) =

=

A die is thrown twice. What is the probability that(i) 5 will not come up either time?(ii) 5 will come up at least once?[Hint: Throwing a die twice and throwing two dice simultaneously are treated as the same experiment]

A die is thrown twice. What is the probability that
(i) 5 will not come up either time?

(ii) 5 will come up at least once?

[Hint: Throwing a die twice and throwing two dice simultaneously are treated as the same experiment]