Classify the following functions as injection, surjection or bijection:
f : R → R, defined by f(x) = x3 – x
TIP: – One – One Function: – A function is said to be a one – one functions or an injection if different elements of A have different images in B.
So, is One – One function
⇔ a≠b
⇒ f(a)≠f(b) for all
⇔ f(a) = f(b)
⇒ a = b for all
Onto Function: – A function is said to be a onto function or surjection if every element of A i.e, if f(A) = B or range of f is the co – domain of f.
So, is Surjection iff for each
, there exists
such that f(a) = b
Bijection Function: – A function is said to be a bijection function if it is one – one as well as onto function.
Now, Let, given by f(x) = x3 + x
Check for Injectivity:
Let x,y be elements belongs to R i.e such that
So, from definition
⇒ f(x) = f(y)
⇒ x3 – x = y3 – y
⇒ x3 – y3 – (x – y) = 0
⇒ (x – y)(x2 + xy + y2 – 1) = 0
Hence f is not One – One function
Check for Surjectivity:
Let y be element belongs to R i.e be arbitrary, then
⇒ f(x) = y
⇒ x3 – x = y
⇒ x3 – x – y = 0
Now, we know that for 3 degree equation has a real root
So, let be that root
⇒
Thus for clearly , there exist
such that f(x) = y
Therefore f is onto
Thus, It is not Bijective function