Classify the following functions as injection, surjection or bijection:

f: Q – {3} Q, defined by

TIP: One – One Function: – A function is said to be a one – one functions or an injection if different elements of A have different images in B.


So, is One – One function


a≠b


f(a)≠f(b) for all


f(a) = f(b)


a = b for all


Onto Function: – A function is said to be a onto function or surjection if every element of A i.e, if f(A) = B or range of f is the co – domain of f.


So, is Surjection iff for each , there exists such that f(a) = b


Bijection Function: – A function is said to be a bijection function if it is one – one as well as onto function.


Now, f : R R given by


Check for Injectivity:


Let x,y be elements belongs to Q i.e such that


f(x) = f(y)



(2x + 3)(y – 3) = (2y + 3)(x – 3)


2xy – 6x + 3y – 9 = 2xy – 6y + 3x – 9


– 6x + 3y = – 6y + 3x


– 6x + 3y + 6y – 3x = 0


– 9x + 9y = 0


x = y


Thus, f is One – One function


Check for Surjectivity:


Let y be element belongs to Q i.e be arbitrary, then


f(x) = y



2x + 3 = y (x – 3)


2x + 3 = xy – 3y


2x – xy = – 3(y + 1)



Above value of x belongs to Q – [3] for y = 2


Therefore for each element in Q – [3] (co – domain), there does not exist an element in domain Q.


Hence, f is not onto function


Thus, Not Bijective function


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