If A = {1, 2, 3}, show that an onto function f : A → A must be one – one.
TIP: – One – One Function: – A function is said to be a one – one functions or an injection if different elements of A have different images in B.
So, is One – One function
⇔ a≠b
⇒ f(a)≠f(b) for all
⇔ f(a) = f(b)
⇒ a = b for all
Onto Function: – A function is said to be a onto function or surjection if every element of A i.e, if f(A) = B or range of f is the co – domain of f.
So, is Surjection iff for each
, there exists
such that f(a) = b
Now, f : A → A where A = {1, 2, 3} and its an Onto function
To Prove: – A is a One – One function
Let's assume f is not Onto function,
Then,
There must be two elements let it be 1 and 2 in Domain A = {1, 2, 3} whose images in co–domain A = {1, 2, 3} is same.
Also, Image of 3 under f can be only one element.
Therefore,
Range set can have at most two elements in co – domain A = {1, 2, 3}
⇒ f is not an onto function
Hence it contradicts
⇒ f must be One – One function
Hence Proved