Find fog and gof, if

f(x) = x + 1, g(x) = 2x + 3

f(x) = x + 1 and g(x) = 2x + 3


Range of f = R Domain of g = R gof exists


Range of g= R Domain of f fog exists


Now,


fog(x) = f(g(x) = f(2x + 3) = (2x + 3) + 1= 2x + 4 and


gof(x)= g(f(x))= g(x + 1) = 2(x + 1) + 3 = 2x + 5


So, fog(x) = 2x + 4 and gof(x) = 2x + 5


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