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Find the principal values of each of the following:
sec–1(–√2)
Let sec–1(–√2) = y
⇒ sec y = –√2
= – sec = √2
= sec
= sec
The range of principal value of sec–1is [0, π]–{}
and sec = –√2
∴ The principal value of sec–1(–√2) is .