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Find the principal values of each of the following:

sec^{–1}(2)

Let sec^{–1}(2) = y

⇒ sec y = 2

⇒ sec()

The range of principal value of sec^{–1}is [0, π]–{}

And sec = 2

∴ The principal value of sec^{–1}(2) is .

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