Find the principal values of each of the following:
cosec–1(–√2)
cosec–1 (–√2) =y
⇒ cosec y = –√2
⇒ –cosec y = √2
⇒ –cosec
= √2
As we know cosec(–θ) = –cosecθ
∴ –cosec
= cosec ![]()
The range of principal value of cosec–1 is
–{0} and
cosec
= –√2
Therefore, the principal value of cosec–1(–√2) is
.