Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at the point O. Using a similarity criterion for two triangles, show that
In ΔDOC and ΔBOA,
∠CDO = ∠ABO (Alternate interior angles as AB || CD)
∠DCO = ∠BAO (Alternate interior angles as AB || CD)
∠DOC = ∠BOA (Vertically opposite angles)
Therefore,
(Corresponding sides are proportional)
,