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Find the principal values of each of the following:
cosec–1(–2)
cosec–1–2 = y
⇒ cosec y = –2
⇒ –cosec y = 2
⇒ –cosec = 2
As we know cosec(–θ) = –cosecθ
∴ –cosec = cosec
The range of principal value of cosec–1 is –{0} and
cosec = –2
Therefore, the principal value of cosec–1(–2) is .