For the principal values, evaluate the following:

We can write,
tan
= tan (2π –
)
tan(2π – θ )
= tan(–θ)
= –tanθ
∴ tan
becomes –tan![]()
–tan
= –![]()
⇒ 2tan
= –![]()
∴ The question converts to cosec–1(–
)
Let cosec–1
= y
⇒ cosec y = ![]()
= cosec![]()
The range of principal value of cosec–1 is
–{0}
and cosec![]()
Therefore, the principal value of cosec–1
is
.