Evaluate each of the following:

The value of sin is

∴ The question becomes sin^{–1}

Let sin^{–1} ^{=} y

⇒ sin y =

= sin

The range of principal value of sin^{–1} is and sin

Therefore, the value of sin^{–1}(sin) is .

**Alternate Solution:**

sin^{–1}(sin x) = x

Provided x ϵ

∴ we can write sin^{–1}(sin) =

1