The value of sin is

∴ The question becomes sin^–1

Let sin^{–1 =} y

⇒ sin y =

= sin

The range of principal value of sin^–1 is and sin

Therefore, the value of sin^–1(sin) is .

Alternate Solution:

sin^–1(sin x) = x

Provided x ϵ

∴ we can write sin^–1(sin) =