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Evaluate each of the following:
The value of sin is
∴ The question becomes sin–1
Let sin–1 = y
⇒ –sin y =
= –sin
As, –sin(θ) is sin(–θ).
⇒ –sin = sin
The range of principal value of sin–1 is and sin
Therefore, the value of sin–1(sin) is
.