Evaluate each of the following:
We can write (sin
) as sin
As we know sin(2π –θ) = sin(–θ )
So sin
can be written as sin
∴ The equation becomes sin–1(sin
)
As sin–1(sin x) = x
Provided x ϵ 
∴ we can write sin–1(sin
) = 
1
Evaluate each of the following:
We can write (sin) as sin
As we know sin(2π –θ) = sin(–θ )
So sin can be written as sin
∴ The equation becomes sin–1(sin)
As sin–1(sin x) = x
Provided x ϵ
∴ we can write sin–1(sin) =