Evaluate each of the following:
As we know sin(–θ) is –sin(θ )
∴ We can write (sin) as –sin
Now –sin–sin
As we know sin(2π +θ) = sin(θ )
So –sin can be written as –sin
And –sin = sin
The equation becomes sin–1(sin)
As sin–1(sin x) = x
Provided x ϵ
∴ we can write sin–1(sin) =