Evaluate each of the following:

As we know sin(–θ) is –sin(θ )

∴ We can write (sin) as –sin

Now –sin–sin

As we know sin(2π +θ) = sin(θ )

So –sin can be written as –sin

And –sin = sin

The equation becomes sin^{–1}(sin)

As sin^{–1}(sin x) = x

Provided x ϵ

∴ we can write sin^{–1}(sin) =

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