Evaluate each of the following:

As we know sin(–θ) is –sin(θ )


We can write (sin) as –sin


Now –sin–sin


As we know sin(2π +θ) = sin(θ )


So –sin can be written as –sin


And –sin = sin


The equation becomes sin–1(sin)


As sin–1(sin x) = x


Provided x ϵ


we can write sin–1(sin) =


1