Evaluate each of the following:

As we know sin(–θ) is –sin(θ )
∴ We can write (sin
) as –sin![]()
Now –sin
–sin![]()
As we know sin(2π +θ) = sin(θ )
So –sin
can be written as –sin![]()
And –sin
= sin![]()
The equation becomes sin–1(sin
)
As sin–1(sin x) = x
Provided x ϵ ![]()
∴ we can write sin–1(sin
) = ![]()