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Evaluate each of the following:
sin–1(sin3)
sin–1(sin x) = x
Provided x ϵ ≈ [–1.57,1.57]
And in our equation x is 3 which does not lie in the above range.
We know sin[π – x] = sin[x]
∴ sin(π – 3) = sin(3)
Also π–3 belongs in
∴ sin–1(sin3) = π–3