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Evaluate each of the following:
sin–1 (sin12)
sin–1(sin x) = x
Provided x ϵ ≈ [–1.57,1.57]
And in our equation x is 4 which does not lie in the above range.
We know sin[2nπ – x] = sin[–x]
∴ sin(2nπ – 12) = sin(–12)
Here n = 2
Also 2π–12 belongs in
∴ sin–1(sin12) = 2π – 12