sin^–1(sin x) = x

Provided x ϵ ≈ [–1.57,1.57]

And in our equation x is 3 which does not lie in the above range.

We know sin[π – x] = sin[x]

∴ sin(π – 2) = sin(2)

Also π–2 belongs in

∴ sin^–1(sin2) = π–2