Evaluate each of the following:

tan–1 (tan 2)

As, tan–1(tan x) = x


Provided x ϵ


Here our x is 2 which does not belong to our range


We know tan(π –θ) = –tan(θ)


tan(θ –π ) = tan(θ)


tan(2–π ) = tan(2)


Now 2–π is in the given range


tan–1 (tan 2) = 2–π


3